How do you factor $y = 6 x^{2} + 20 x + 6$ $y= 6x^2 + 20x + 6$ ?

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How do you factor $y = 6 x^{2} + 20 x + 6$ $y= 6x^2 + 20x + 6$ ?

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Answer 1 · 2016-02-28T06:06:11

y = 2(3x + 1)(x + 3)

Explanation:

Use the new AC Method to factor trinomial. (Socratic Search)
$y = 6 x^{2} + 20 x + 6$ $y = 6x^2 + 20x + 6$ .
Converted trinomial: $x^{2} + 20 x + 36 =$ $x^2 + 20x + 36 =$ (x + p')(x + q').
Factor pairs of 36 --> (2, 18) This sum is 20 = b. Then p' = 2 and q' = 18
Back to original trinomial: $p = \frac{2}{6} = \frac{1}{3}$ $p = 2/6 = 1/3$ and $q = \frac{18}{6} = 3 .$ $q = 18/6 = 3.$
Factored form: $y = 6 (x + \frac{1}{3}) (x + 3) = 2 (3 x + 1) (x + 3)$ $y = 6(x + 1/3)(x + 3) = 2(3x + 1)(x + 3)$

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How do you factor $y = 6 x^{2} + 20 x + 6$ $y= 6x^2 + 20x + 6$ ?

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How do you factor y=6x2+20x+6y= 6x^2 + 20x + 6 ?

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How do you factor $y = 6 x^{2} + 20 x + 6$ $y= 6x^2 + 20x + 6$ ?