How do you factor #y= 6x^2 + 20x + 6# ?

1 Answer
Feb 28, 2016

Answer:

y = 2(3x + 1)(x + 3)

Explanation:

Use the new AC Method to factor trinomial. (Socratic Search)
#y = 6x^2 + 20x + 6#.
Converted trinomial: #x^2 + 20x + 36 =# (x + p')(x + q').
Factor pairs of 36 --> (2, 18) This sum is 20 = b. Then p' = 2 and q' = 18
Back to original trinomial: #p = 2/6 = 1/3# and #q = 18/6 = 3.#
Factored form: #y = 6(x + 1/3)(x + 3) = 2(3x + 1)(x + 3)#