How do you factor: $y = n^{2} - 7 n + 12$ $y= n^2-7n+12$ ?

Question

2581 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-22T10:04:19

$y = (n - 3) (n - 4)$ $y=(n-3)(n-4)$

$y = n^{2} - 7 n + 12$ $y=n^2-7n+12$

$Delta=1$
For $y=0$ , $n_1=(7-sqrtDelta)/2, n_2=(7+sqrtDelta)/2$

Therefore,
$y=(n-3)(n-4)$

How do you factor: y= n^2-7n+12 y=n2−7n+12y= n^2-7n+12 ?