Question

How do you factor: #y= n^2-7n+12 #?

Answer 1

`y=(n-3)(n-4)`

Explanation:

`y=n^2-7n+12`

`Delta=1`
For `y=0`, `n_1=(7-sqrtDelta)/2, n_2=(7+sqrtDelta)/2`

Therefore,
`y=(n-3)(n-4)`