# How do you factor y=x^2 + 4x - 5 ?

##### 1 Answer

If you mean to write it as a parabola in the form $y = a \cdot {\left(x - h\right)}^{2} + k$

we have that

$y = \left({x}^{2} + 4 x + 4\right) - 9 = {\left(x + 2\right)}^{2} - 9$

If you mean to factor the LHS it is as follows

y=x^2 + 4x - 5=>y=x^2+4x-4-1=> y=(x^2-1)+4(x-1)=> y=(x-1)(x+1)+4(x-1)=> y=(x-1)*(x+5)

The graph of $y$ is