Question

How do you factor: #y= x^3 + 64 #?

Answer 1

`y = (x+4)*(x^2 -4x +16)`.
(It's still possible to factorize the second degree polynomial, with complex numbers as roots)

Explanation:

Remember the rule `a^3+b^3 = (a+b)*(a^2-ab+b^2)`. In the case, `b^3 = 64` so `b = 4`.