# How do you factor: y= x^3 + 64 ?

$y = \left(x + 4\right) \cdot \left({x}^{2} - 4 x + 16\right)$.
Remember the rule ${a}^{3} + {b}^{3} = \left(a + b\right) \cdot \left({a}^{2} - a b + {b}^{2}\right)$. In the case, ${b}^{3} = 64$ so $b = 4$.