# How do you factor y=x^3 + 6x^2 + 8x ?

Jul 22, 2016

$y = x \left(x + 2\right) \left(x + 4\right)$

#### Explanation:

Take common factor of x out leaving a quadratic inside:

$y = x \left({x}^{2} + 6 x + 8\right)$

Fairly easy to solve by eye but will use quadratic formula for completeness:

$x = \frac{- 6 \pm \sqrt{{6}^{2} - 4 \cdot 1 \cdot 8}}{2} = \frac{- 6 \pm \sqrt{4}}{2}$

$\implies x = - 2 \mathmr{and} x = - 4$

Hence

$y = x \left(x + 2\right) \left(x + 4\right)$