Question

How do you factor `y= (x-5)(x+6)^2 - (x-5)^2 (x+6)` ?

Answer 1

`y=(x-5)(x+6)(11)`

Explanation:

When factorising, you want to take out anything that you can find in both parts of the equation ie in `(x-5)(x+6)^2` and `(x-5)^2(x+6)`

Hopefully, you will notice that there is one `x-5` and one `x+6` in both parts

Therefore, you can "take" them out
`y=(x-5)(x+6)(x+6-(x-5))`
`y=(x-5)(x+6)(x+6-x+5)`
`y=(x-5)(x+6)(11)`