# How do you factor y= (x-5)(x+6)^2 - (x-5)^2 (x+6)  ?

Jul 4, 2018

$y = \left(x - 5\right) \left(x + 6\right) \left(11\right)$

#### Explanation:

When factorising, you want to take out anything that you can find in both parts of the equation ie in $\left(x - 5\right) {\left(x + 6\right)}^{2}$ and ${\left(x - 5\right)}^{2} \left(x + 6\right)$

Hopefully, you will notice that there is one $x - 5$ and one $x + 6$ in both parts

Therefore, you can "take" them out
$y = \left(x - 5\right) \left(x + 6\right) \left(x + 6 - \left(x - 5\right)\right)$
$y = \left(x - 5\right) \left(x + 6\right) \left(x + 6 - x + 5\right)$
$y = \left(x - 5\right) \left(x + 6\right) \left(11\right)$