How do you factor #(z + 3)2 - 9(z + 3)#?
1 Answer
Jun 20, 2018
Explanation:
#"take out the "color(blue)"common factor "(z+3)#
#=(z+3)(2-9)=-7(z+3)#
#"take out the "color(blue)"common factor "(z+3)#
#=(z+3)(2-9)=-7(z+3)#