How do you factorize $20 p + 15 p q - 60 q^{2} - 80 q$ $20p + 15pq - 60q^2-80q$ completely?

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How do you factorize $20 p + 15 p q - 60 q^{2} - 80 q$ $20p + 15pq - 60q^2-80q$ completely?

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Answer 1 · 2017-12-02T18:23:56

$5 (4 + 3 q) (p - 4 q)$ $5(4+3q)(p-4q)$

Explanation:

$= 20 p - 80 q + q (15 p - 60 q)$ $= 20p-80q+q(15p-60q)$
$= 20 (p - 4 q) + 15 q (p - 4 q)$ $= 20(p-4q) + 15q(p-4q)$
$= (20 + 15 q) (p - 4 q)$ $= (20+15q)(p-4q)$
$= 5 (4 + 3 q) (p - 4 q)$ $= 5(4+3q)(p-4q)$

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How do you factorize $20 p + 15 p q - 60 q^{2} - 80 q$ $20p + 15pq - 60q^2-80q$ completely?

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Explanation:

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How do you factorize 20p+15pq−60q2−80q20p + 15pq - 60q^2-80q completely?

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Explanation:

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How do you factorize $20 p + 15 p q - 60 q^{2} - 80 q$ $20p + 15pq - 60q^2-80q$ completely?