# How do you find a possible value for a if the points (a,0), (3,1) has a distance of #d=sqrt2#?

##### 1 Answer

May 14, 2017

#### Answer:

#### Explanation:

The distance between two points

Hence distance between

as this is equal to

or

i.e.

or

i.e.

graph{((x-2)^2+y^2-0.01)((x-4)^2+y^2-0.01)((x-3)^2+(y-1)^2-0.01)=0 [-3.11, 6.89, -1.92, 3.08]}