# How do you find a standard form equation for the line with (-9, -6) and is parallel to the line whose equation is 7x - 8y + 10 = 0?

The equation of the line is $y = \frac{7}{8} x + \frac{15}{8}$
The slope of the line$7 x - 8 y + 10 = 0 \mathmr{and} 8 y = 7 x + 10 \mathmr{and} y = \frac{7}{8} x + \frac{10}{8}$is $\frac{7}{8}$[Comparing with slope-intercept form of line $y = m x + c$]. So the slope of the parallal line is also $\frac{7}{8} \therefore$The equation of the line with$\left(- 9 , - 6\right)$ and having slope$\frac{7}{8}$ is $y - {y}_{1} = m \left(x - {x}_{1}\right) \mathmr{and} y + 6 = \frac{7}{8} \left(x + 9\right) \mathmr{and} \mathmr{and} y = \frac{7}{8} x + \frac{63}{8} - 6 \mathmr{and} y = \frac{7}{8} x + \frac{15}{8}$[Ans]