How do you find all real number solutions to root3(2x+3)-1=0?

Nov 13, 2016

$\sqrt[3]{2 x + 3} = 1$

${\left(2 x + 3\right)}^{\frac{1}{3}} = 1$

${\left({\left(2 x + 3\right)}^{\frac{1}{3}}\right)}^{3} = {1}^{3}$

$2 x + 3 = 1$

$2 x = - 2$

$x = - 1$

Hopefully this helps!