# How do you find all the critical points to graph #x^2 - y^2 + 9 = 0# including vertices, foci and asymptotes?

##### 1 Answer

#### Answer:

**Center:** **vertices are at** **focii are at****equation of asymptotes
of vertical hyperbola are**

#### Explanation:

hyperbola is

Here

Vertices are

are at

that intersect at the center of the hyperbola. The asymptotes

pass through the vertices of a rectangle of dimensions

slope

graph{x^2-y^2+9=0 [-10, 10, -5, 5]}[Ans]