How do you find all the zeros of f(x) = 3(x+5)(x+2)^2 ?

Mar 25, 2016

Zeros of $f \left(x\right)$ are $- 5$ and $- 2$.
If $a$ is a zero for a function $f \left(x\right)$, then $f \left(a\right) = 0$.
As the given $f \left(x\right) = 3 \left(x + 5\right) {\left(x + 2\right)}^{2} = 0$ for $x + 5 = 0$ and $x + 2 = 0$,
the zeros of $f \left(x\right)$ are $- 5$ and $- 2$.