Question

How do you find `cos^-1(sin((5pi/4))`?

Answer 1

`(2n+1)pi+-pi/4, n=0, +-1, +-2, +-3,..`

Explanation:

`cos^(-1)(sin ((5pi)/4)=cos^(-1)sin(pi+pi/4)=cos^(-1)(-1/sqrt 2)`

`= (2n+1)pi+-pi/4, n=0, +-1, +-2, +-3,..`