How do you find electron configuration using the periodic table?

1 Answer
Jul 12, 2017

Answer:

Well what is #"Z, the atomic number"# of the element.......?

Explanation:

#Z# gives the number of nuclear protons, and the number of electrons that we have to distribute according to a given scheme......

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The scheme is not perfect, and it falls down for chromium metal, which is #Z=24#, and gives #1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^1# rather than but #1s^2 2s^2 2p^6 3s^2 3p^6 3d^4 4s^2#, but you can learn this and several other exceptions.......

The features the filling of the #"4s-orbitals"# BEFORE the #"3d-orbitals"# begin to be filled.....And thus the first-row transition metals typically have a FULL #4s# shell, cf. iron, #Z=26#, and gives #1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6 #

And given the position of the element on the Periodic Table, #"s-block"#, #"p-block"#, #"d-block"#, usually you can define the valence configuration without difficulty.

Anyway, this is the knowledge expected of an undergraduate student. I don't know whether you are there or at A-level.