# How do you find point-slope form given x-intercept=9 and y-intercept=-4?

$y = \frac{4}{9} \left(x - 9\right)$
The line joining the two intercepts is depicted in the figure. The slope of the line would be $\tan \theta$ as shown there.
Slope of this line would be $\frac{4}{9}$. It passes through point (9,0), hence point slope form would be
$y - 0 = \frac{4}{9} \left(x - 9\right)$ or simply $y = \frac{4}{9} \left(x - 9\right)$