# How do you find sin(sin^-1 (1/4))?

Answer is $\frac{1}{4}$
Recall that $\sin \left[\arcsin \left(x\right)\right] = x$ for $x$ in the domain of $\arcsin \left(x\right)$.
(The domain of $\arcsin \left(x\right)$ is: $- 1 \le x \le 1$.)
Therefore $\sin \left[\arcsin \left(\frac{1}{4}\right)\right] = \frac{1}{4.}$