Question

How do you find `sin(sin^-1 (1/4))`?

Answer 1

Answer is `1/4`
Recall that `sin[arcsin(x)] = x` for `x` in the domain of `arcsin(x)`.

(The domain of `arcsin(x)` is: `-1 <= x <= 1`.)

Therefore `sin[arcsin(1/4)] = 1/4.`