# How do you find slope and intercepts to graph 2x-3y=3?

Slope $= \frac{2}{3}$, x-intercept $= \frac{3}{2}$ & y-intercept $= - 1$

#### Explanation:

The given straight line:

$2 x - 3 y = 3$

$y = \frac{2}{3} x - 1$

Comparing above equation with the standard form of slope-intercept: $y = m x + c$ , we get

Slope: $m = \frac{2}{3}$

Re-writing the equation of straight line as follows

$\frac{x}{\frac{3}{2}} + \frac{y}{- 1} = 1$

Comparing above equation with the intercept form: $\frac{x}{a} + \frac{y}{b} = 1$, we get

x-intercept: $a = \frac{3}{2}$

y-intercept: $b = - 1$