# How do you find the absolute value of sqrt11+isqrt5?

Aug 21, 2016

$| \sqrt{11} + i \sqrt{5} | = 4$

#### Explanation:

The absolute value of a complex number $a + b i$ is written as $| a + b i |$ and its value is $\sqrt{{a}^{2} + {b}^{2}}$.

Hence, absolute value of $\sqrt{11} + i \sqrt{5}$ is

$| \sqrt{11} + i \sqrt{5} |$

= $\sqrt{{\left(\sqrt{11}\right)}^{2} + {\left(\sqrt{5}\right)}^{2}}$

= $\sqrt{11 + 5}$

= $\sqrt{16}$

= $4$.