How do you find the absolute value of #sqrt11+isqrt5#?

1 Answer
Aug 21, 2016

#|sqrt11+isqrt5|=4#

Explanation:

The absolute value of a complex number #a+bi# is written as #|a+bi|# and its value is #sqrt(a^2+b^2)#.

Hence, absolute value of #sqrt11+isqrt5# is

#|sqrt11+isqrt5|#

= #sqrt((sqrt11)^2+(sqrt5)^2)#

= #sqrt(11+5)#

= #sqrt16#

= #4#.