How do you find the amplitude and period of y= 2sin(pi*x)?

2 Answers

2 & 2

Explanation:

The periodic function y=2\sin(\pi x)

Amplitude =2

Period ={2\pi}/ \pi=2

Jul 4, 2018

Amplitude = 2, Period = 2#

Explanation:

y = A sin (Bx - C) + D

Given y = 2 sin (pi x)

A = 2, B = pi, C = D = 0

Amplitude = |A| = 2

Period = (2pi)/|B| = (2pi) / pi = 2

Phase Shift = -C / B = 0

Vertical Shift = D = 0