# How do you find the amplitude and period of y=sec(8pit)?

Nov 12, 2017

Amplitude $= 1$, Period $= \frac{1}{4}$

#### Explanation:

Standard form of equation is
$y = a \sec \left(b t - c\right) + d$

$a = 1 , b = 8 \pi$

Amplitude $a = 1$

Period $= \frac{2 \pi}{|} b |$

Period $= \left(\frac{\cancel{2 \pi}}{\cancel{8 \pi} 4}\right) = \frac{1}{4}$