# How do you find the amplitude, period and phase shift for y=3+5sin2(theta-pi)?

Aug 23, 2017

Write in the standard form

$y = A \sin \left(B \theta + C\right) + D$

$y = 5 \sin \left(2 \theta - 2 \pi\right) + 3$

The amplitude, A, is:

$A = 5$

The period, P, is:

$P = \frac{2 \pi}{B}$

$P = \frac{2 \pi}{2}$

$P = \pi$

The phase shift, $\phi$, is:

$\phi = - \frac{C}{B}$

$\phi = - \frac{- 2 \pi}{2}$

$\phi = \pi$

The vertical shift, D, is:

$D = 3$