# How do you find the amplitude, period and phase shift for y=cos(theta+180^circ)?

Mar 1, 2018

color(blue)(Amplitude = 1, Period = 2pi, Phase shift $\textcolor{b l u e}{- \pi}$ color(white)(aa) color(red)((pi^c) to the left

#### Explanation:

Using the standard form of equation $y = a \cos \left(b \theta - c\right) + d$,

find amplitude and phase shift of the given equation.

Given $y = \cos \left(\theta + 180\right)$

$a = 1 , b = 1 , c = - 180 , d = 0$

Amplitude $= a = 1$

Period $= \frac{2 \pi}{|} b | = 2 \pi$

Phase shift $\frac{c}{b} = - 180$. (pi^c to the left)

graph{cos(x + pi) [-10, 10, -5, 5]} + pi) [-10, 10, -5, 5]}