Question

How do you find the amplitude, period and phase shift for `y=tan(1/2(theta+30^circ))`?

Answer 1

There is no amplitude for a tangent function due to the behaviour of the function when it approaches its asymptotes.

The period is given by `(180˚)/b = (180˚)/(1/2) = 360˚`

The phase shift is `30˚` to the left.

Here is the graph of the function

Hopefully this helps!