# How do you find the amplitude, period, and shift for y = -2sin (2x-3/2)??

Jan 2, 2016

#amplitude = 2, period = pi , shift = 3/2 to the right.

#### Explanation:

$a \sin \left(b x + c\right)$ defines the sine waveform
a represents the amplitude in this case a = 2 (the - means that the graph will be reflected in the x-axis)
the period of $\sin x i s 2 \pi r a \mathrm{di} a n s$
the period of $\sin 2 x = 2 \frac{\pi}{2} = \pi$ ie period = $2 \frac{\pi}{b}$

c denotes shift +c shifts c units left and -c c units to the right

hence c = 3/2 units to the right