# How do you find the angle alpha such that 0<=alpha<=90 and secalpha=1.080?

Jul 22, 2016

$a = {67}^{\circ} 81$

#### Explanation:

sec a = 1/(sin a) = 1.080
sin a = 1/(1.080) = 0.926
Calculator gives: arc $a = {67}^{\circ} 81$