How do you find the angle #alpha# such that the angle lies in quadrant II and #cotalpha=-0.3899#?
Tangent. and so, cotangent is negative in Q2. and Q4. For a
negative cotangent, the angle in Q4 [-pi/2, 0] is called the principal
The Q2 value can be selected from the general value.
The general value is
The minimum Q2-value is obtained for n = 1 as