# How do you find the angle alpha such that the angle lies in quadrant II and cscalpha=1.244?

Jan 22, 2017

${126}^{\circ} 50$

#### Explanation:

$\csc a = \frac{1}{\sin a} = 1.244$
$\sin a = \frac{1}{1.244} = 0.80$
Calculator gives -->
sin a = 0.80 --> $a = {53}^{\circ} 50$
Trig unit circle gives another angle a (arc a) , in Quadrant II, that has the same sin value (0.80) -->
$a = 180 - 53.50 = {126}^{\circ} 50$