How do you find the antiderivative of #7s^-1#?
1 Answer
Jan 17, 2017
Explanation:
We know that
#d/dx(lnx)=1/x=x^-1# Hence the antiderivative of
#1/x=x^-1" is " ln|x|#
#rArrint7s^-1ds=7ln|s|+c# where c is the constant of integration.
