How do you find the antiderivative of cos pi x? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer Monzur R. Nov 9, 2017 intcospixdx=(sinpix)/pi+"c" Explanation: For the integrand cospix, let u=pix and du=pidx. Then intcospixdx=1/piintcosudu=sinu/pi+"c"=(sinpix)/pi+"c" Answer link Related questions How do I evaluate the indefinite integral intsin^3(x)*cos^2(x)dx ? How do I evaluate the indefinite integral intsin^6(x)*cos^3(x)dx ? How do I evaluate the indefinite integral intcos^5(x)dx ? How do I evaluate the indefinite integral intsin^2(2t)dt ? How do I evaluate the indefinite integral int(1+cos(x))^2dx ? How do I evaluate the indefinite integral intsec^2(x)*tan(x)dx ? How do I evaluate the indefinite integral intcot^5(x)*sin^4(x)dx ? How do I evaluate the indefinite integral inttan^2(x)dx ? How do I evaluate the indefinite integral int(tan^2(x)+tan^4(x))^2dx ? How do I evaluate the indefinite integral intx*sin(x)*tan(x)dx ? See all questions in Integrals of Trigonometric Functions Impact of this question 25698 views around the world You can reuse this answer Creative Commons License