# How do you find the antiderivative of f(x)=sqrt3(x^2)?

It is ${x}^{3} / \sqrt{3}$
$F \left(x\right) = \int f \left(x\right) \mathrm{dx} \implies F \left(x\right) = \int \sqrt{3} \cdot {x}^{2} \mathrm{dx} = \sqrt{3} \cdot \int {x}^{2} \mathrm{dx} = \sqrt{3} \cdot {x}^{3} / 3 = {x}^{3} / \sqrt{3}$