How do you find the antiderivative of #f(x)=(x^2-x)/x#?
1 Answer
Feb 11, 2017
Explanation:
Note that
#(x^2-x)/x=x^2/x-x/x=x-1#
#rArrint(x-1)dx=1/2x^2-x+c# where c is the constant of integration.
