Question

How do you find the `Arccos (sqrt3/2)`?

Answer 1

`pi/3; (5pi)/3`

Explanation:

Trig table and unit circle give -->
`cos x = sqrt3/2` --> arc `x = +- pi/3`
The arc co-terminal to `(-pi/3)` is `(5pi)/3`.
Answers for `(0, 2pi)`:
`pi/3, (5pi)/3`