# How do you find the area of a triangle with sides 8, 15, and 17?

Jun 15, 2015

Find area of triangle ABC

#### Explanation:

Use the trig identity: a^2 = b^2 + c^2 - 2bc cos A

${17}^{2} = {8}^{2} + {15}^{2} - 2 \left(8\right) \left(15\right) . \cos A$

Because: 17^2 = 289 = 64 + 225 = 289, therefor, the triangle is a right triangle with A = 90 deg.

The triangle area : $s = \frac{8 \left(15\right)}{2} = 60$