How do you find the area of the triangle given a=28.16 cm, b=60.15 cm, c=51.17 cm?

Jun 27, 2016

$11.81016511$ $C {m}^{2}$

Explanation:

Area of a triangle whose sides have lengths a, b, and c is

A=sqrt {s(s-a)(s-b)(s-c)

where s is the semiperimeter of the triangle; that is,

$s = \frac{a + b + c}{2}$

$s = \frac{28.16 + 60.15 + 51.17}{2}$ $= 69.74$

A = sqrt (69.74* (69.74 - 28.16)*(69.74 - 60.15)*(69.74 - 51.17)

$A = \sqrt{69.74 \cdot 41.58 \cdot 9.59 \cdot 18.57}$ = $11.81016511$