# How do you find the area of triangle ABC given a=10, B=95, c=35?

Jan 25, 2018

$A = 174.3 \setminus {\text{units}}^{2}$

#### Explanation:

Well, I'm assuming that you are saying that side $a = 10$, side $c = 35$, and angle $B = {95}^{\circ}$.

We can use the formula to find the area of the triangle:

$A = \frac{1}{2} a c \sin B$

Plugging in,

$A = \frac{1}{2} \cdot 10 \cdot 35 \sin 95$

$A = 175 \sin 95$

$A = 174.3 \setminus {\text{units}}^{2}$