# How do you find the area of triangle ABC given a=10, c=8, sinB=3/10?

Feb 10, 2017

${A}_{\Delta A B C} = 12 \text{ sq units}$

#### Explanation:

$\text{area of triangle is given by: }$

${A}_{\Delta} = \frac{1}{2} a b \sin C$

or

${A}_{\Delta} = \frac{1}{2} b c \sin A$

or

${A}_{\Delta} = \frac{1}{2} a c \sin B$

in this case will need the last form

${A}_{\Delta} = \frac{1}{2} \cancel{10} \times 8 \times \frac{3}{\cancel{10}}$

${A}_{\Delta A B C} = \frac{24}{2} = 12 \text{ sq units}$