How do you find the area of #triangle ABC# given a=10, c=8, sinB=3/10?

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Answer 1 · 2017-02-10T10:15:13

#A_(DeltaABC)=12 " sq units"#

#"area of triangle is given by: "#

#A_Delta=1/2 a bsinC#

or

#A_Delta=1/2 b csinA#

or

#A_Delta=1/2 a csinB#

in this case will need the last form

#A_Delta=1/2 cancel(10)xx8xx3/cancel(10)#

#A_(DeltaABC)=24/2=12 " sq units"#