# How do you find the area of triangle ABC given a=24, b=12, sinC=3/4?

Apr 6, 2018

$108 \text{ sq.unit}$.

#### Explanation:

From Trigonometry, we know that,

the Area of

$\Delta A B C = \frac{1}{2} \cdot a \cdot b \sin C = \frac{1}{2} \cdot 24 \cdot 12 \cdot \frac{3}{4} = 108 \text{ sq.unit}$.