How do you find the area of triangle ABC given a=326, c=157, mangleB=72?

Dec 26, 2016

$24338.5$

Explanation:

Area of a triangle - "side angle side" (SAS) method :

Area $= \frac{1}{2} \cdot a \cdot b \cdot \sin C$
where $a , b$ are the two known sides and $C$ is the included angle.

Given $a = 326 , c = 157 \mathmr{and} \angle B = 72$,
$\implies$ Area $= \frac{1}{2} \cdot a \cdot c \cdot \sin B$
$\implies$ Area$= \frac{1}{2} \cdot 326 \cdot 157 \cdot \sin 72 = 24 , 338.5$ $u n i {t}^{2}$