How do you find the area of #triangle ABC# given b=14.6, c=12.8, #mangleA=56#? Trigonometry Triangles and Vectors Area of a Triangle 1 Answer IDKwhatName Jul 29, 2017 #77.5# Explanation: #"Area of non right-angled triangle" = (a*b*sinC)/2#, where: #a = 14.6# #b=12.8# #C=56# #(12.8*14.6*sin(56^circ))/2=77.4652708~~77.5# Answer link Related questions How do you find the area of a triangle with 3 sides given? What is the area of a equilateral triangle with a side of 12? How do you find the area of a triangleABC, if #angleC = 62^@#, #b = 23.9# , and #a = 31.6#? How do you find the area of a triangleGHI, if #angleI = 15^@#, #g = 14.2# , and #h = 7.9#? What is Heron's formula? When do you use Heron's formula to find area? How do you find the area of a triangle ABC, if #a = 23#, #b = 46# , and #c = 41#? Question #f2e4c How do you find the area of the triangle given c= 4, A= 37 degrees, B= 69 degrees? How do you find the area of the triangle given C=85 degrees, a= 2, B= 19 degrees? See all questions in Area of a Triangle Impact of this question 1460 views around the world You can reuse this answer Creative Commons License