# How do you find the area of triangle ABC given b=14.6, c=12.8, mangleA=56?

Jul 29, 2017

$77.5$

#### Explanation:

$\text{Area of non right-angled triangle} = \frac{a \cdot b \cdot \sin C}{2}$, where:
$a = 14.6$
$b = 12.8$
$C = 56$

$\frac{12.8 \cdot 14.6 \cdot \sin \left({56}^{\circ}\right)}{2} = 77.4652708 \approx 77.5$