# How do you find the area of triangle ABC given b=9, c=16, sinA=5/6?

Mar 6, 2018

$60 \text{ sq.unit}$.

#### Explanation:

Area of $\Delta A B C = \frac{1}{2} b c \sin A = \frac{1}{2} \times 9 \times 16 \times \frac{5}{6} = 60 \text{ sq.unit}$.

Mar 6, 2018

$\triangle = 60$

#### Explanation:

We know that,area of$\triangle A B C = \triangle = \frac{1}{2} b c \sin A$
$\therefore \triangle = \frac{1}{2} \left(9\right) \left(16\right) \left(\frac{5}{6}\right) = 60$