How do you find the area of #triangle ABC# given b=9, c=16, sinA=5/6?

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Answer 1 · 2018-03-06T09:57:14

# 60" sq.unit"#.

Area of #DeltaABC=1/2bcsinA=1/2xx9xx16xx5/6=60" sq.unit"#.

Answer 2 · 2018-03-06T10:10:32

#triangle=60#

We know that,area of#triangleABC=triangle=1/2bcsinA#
#:.triangle=1/2(9)(16)(5/6)=60#