# How do you find the area of triangle ABC given C=116^circ, a=2.7, b=4.6?

Area$\approx 5.582$
The area of the triangle is $\frac{1}{2} \cdot a \cdot b \cdot \sin \left(C\right)$, so:
Area $= \frac{1}{2} \cdot 2.7 \cdot 4.6 \cdot \sin \left({116}^{\circ}\right) \approx 5.582$