How do you find the area of #triangle DEF# given d=5.83, e=5.83, #mangleF=48#?

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Answer 1 · 2018-01-27T01:53:10

#A=12.58 \ "units"^2#

We can find the area of a triangle using trigonometric functions, such as

#A=1/2desinF# in this case

#d=e=5.83#

#F=48#

#:.sinF^@=0.74#

#:A=1/2*5.83*5.83*0.74#

#A~~12.58 \ "units"^2#

Answer 2 · 2018-01-27T01:55:13

Area #triangle DEF approx 12.629341# sq units

Here we have #triangle DEF# given #angle F = 48^o# and the sides opposite both #angle D and angle E = 5.83# units

So we have been given the lengths of two sides and the included angle. We can use the formuls below for the area of #triangle DEF#

Area #triangle DEF = 1/2 d e sinF#
#=1/2xx5.83xx5.83 xx sin(48^o)#

#approx 1/2 xx 33.9889 xx 0.743145#

#approx 12.629341# sq units

NB: Since #triangle DEF# is Isosceles (since #d=e)# other methods could be used to solve this.