Question

How do you find the axis of symmetry and vertex point of the function: `f(x) = -x^2 + 6x - 9`?

Answer 1

Find vertex and axis of symmetry f(x) = -x^2 + 6x - 9

Explanation:

x-coordinate of vertex and axis of symmetry:
x = (-b)/2a = -6/-2 = 3
y-coordinate of vertex:
y = f(3) = - 9 + 18 - 9 = 0.
Note. f(x) = - (x - 3)^2