How do you find the axis of symmetry and vertex point of the function: y=2x^2 + 1?

The function is already in completed square form (explicitly $2 {\left(x - 0\right)}^{2} + 1$), so we can see the axis of symmetry is $x = 0$ (which in fact is the y axis) and the vertex point is $\left(0 , 1\right)$.