# How do you find the axis of symmetry and vertex point of the function: y = 2x^2 – 12x + 22?

Sep 30, 2015

Vertex of $y = 2 {x}^{2} - 12 x + 22$

Ans: Vertex (3, 4)

#### Explanation:

x-coordinate of axis of symmetry and vertex:
$x = \left(- \frac{b}{2} a\right) = \frac{12}{4} = 3$
y-coordinate of vertex:
y = f(3) = 18 - 36 + 22 = 4
graph{2x^2 - 12x + 22 [-20, 20, -10, 10]}