# How do you find the axis of symmetry and vertex point of the function: y=3x^2+12x-2?

##### 1 Answer
Oct 12, 2015

Its vertex is $\left(- 2 , - 14\right)$
its axis of symmetry is $\left(x = - 2\right)$

#### Explanation:

$y = 3 {x}^{2} + 12 x - 2$

Find the vertex point first.

$x = \frac{- b}{2 a} = \frac{- 12}{2 \times 3} = \frac{- 12}{6} = - 2$

At $x = - 2$

$y = 3 \left(- {2}^{2}\right) + 12 \left(- 2\right) - 2$
$y = 12 - 24 - 2$
$y = - 14$

Its vertex is $\left(- 2 , - 14\right)$
its axis of symmetry is $\left(x = - 2\right)$

graph{3x^2+12x-2 [-32.47, 32.5, -16.24, 16.22]}