Question

How do you find the axis of symmetry and vertex point of the function: `y=8(x-10)^2-16`?

Answer 1

Axis of Symmetry: `x=10`
Vertex: `(10,-16)`

Explanation:

For a quadratic equation in vertex form `y=a(x-h)^2+k`, the axis of symmetry is `x=h` and the vertex is `(h,k)`.

Now take a look at your equation:
`y=a(x-h)^2+k`
`y=8(x−10)^2−16`

Here:
`a=8`
`h=10`
`k=-16`

Axis of Symmetry
`x=h`
`color(blue)(x=10)`

Vertex
`(h,k)`
`color(red)((10,-16)`