# How do you find the axis of symmetry, graph and find the maximum or minimum value of the function f(x)=-4(x+1)^2+1?

Jun 15, 2018

Has a maximum at $\left(- 1 , 1\right)$

axis of symmetry $= - 1$

#### Explanation:

This quadratic is in vertex form:

$y = a {\left(x + h\right)}^{2} + k$

$a > 0$ has min at vertex
$a < 0$ has max at vertex

vertex $= \left(- h , k\right)$

axis of symmetry $= - h$

Has a maximum at $\left(- 1 , 1\right)$

axis of symmetry $= - 1$

graph{-4(x+1)^2+1 [-10.08, 9.92, -6.28, 3.72]}