# How do you find the discriminant, describe the number and type of root, and find the exact solution using the quadratic formula given 0.4x^2+x-0.3=0?

Feb 24, 2017

$\frac{- 1 \pm \sqrt{1.48}}{0.8}$

#### Explanation:

$a {x}^{2} + b x + c = 0$, in the quadratic formula is $\sqrt{{b}^{2} - 4 a c}$.
In the present case a= 0.4, b= 1 and c= -0.3, hence the discriminant would be $\sqrt{1 - 4 \left(0.4\right) \left(- 0.3\right)} = \sqrt{1.48}$
Exact solution would be x= (-1+- sqrt 1.48)/(2(0.4)
=$\frac{- 1 \pm \sqrt{1.48}}{0.8}$